Caesar Cipher java my way, doesnt work -
i know there bunch of topics caesar cipher solve things way. , such doesnt work ,but think might work way.i sure know feeling when alone solve problem.
so here idea. make array of chars consist alphabet. , string message code. 2 loops. 1 outer set char message, , inner scans thru alphabet array. when letter message meet char in array, replaces him 3rd (key of 3) char down in array.
here piece of code written now:
char[] alphabet = { 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'o', 'p','r','s','t','u', 'v', 'z'}; string message = " message coding"; message = message.tolowercase(); string codedmsg = ""; for(int = 0; < message.length(); i++) { for(int j =0; j < alphabet.length; j++) { if(message.charat(i) == alphabet[j]) { codedmsg += alphabet[j +3 ]; it complies well, receive following error when run :
exception in thread "main" java.lang.arrayindexoutofboundsexception: 23 @ sifra.main(sifra.java:19)
you're problem have alphabet[j + 3]. because j < alphabet.length, when j = alphabet.length - 2 alphabet[j + 3] becomes alphabet[alphabet.length + 1] go outside array.
to solve can use alphabet[(j + 3)%alphabet.length].
now code run not correct.
because manipulate message replaced many times in inner loop.
for(int j =0; j < alphabet.length; j++) { if(message.charat(i) == alphabet[j]) { message = message.replace(message.charat(i), alphabet[j + 3]); // line problem if message.charat(i) = a true if(message.charat(i) == alphabet[j]) , a in sting change d message.charat(i) = d , after 3 iteration of for(int j =0; j < alphabet.length; j++) if statement true again , d in string replaced g , on. solution problem following there many more:
char[] alphabet = { 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'o', 'p','r','s','t','u', 'v', 'z'}; string message = " message coding"; message = message.tolowercase(); char[] messagearray = message.tochararray(); for(int = 0; < message.length(); i++) { for(int j =0; j < alphabet.length; j++) { if(message.charat(i) == alphabet[j]){ messagearray[i] = alphabet[(j + 3)%alphabet.length]; } } } system.out.println(string.copyvalueof(messagearray));