Firebase Java Query.equalTo() does not work -

i trying understand how method works. have set , pushed strings root of firebase. made reference firebase , trying make query object way

query refq = ref.orderbyvalue().equalto(word); 

where word same string pushed firebase.

i want print value console. weird thing happens console hangs in infinite loop , need force terminate. put print statement after above line of code , never gets reached.

so question is, doing wrong?

edit: forgot mention word static , 1 of words pushed firebase. doing test functionality.

i created minimal sample , ran in jdk 1.8.0_31:

public static void main(string[] args) throws exception {     firebase ref = new firebase("https://stackoverflow.firebaseio.com/29553461");      /*     map<string,object> map = new hashmap<string, object>();     map.put("puf", "frank van puffelen");     map.put("frank", "frank van puffelen");     map.put("david", "david east");     map.put("east", "david east");     ref.setvalue(map);     */      query refq = ref.orderbyvalue().equalto("frank van puffelen");     refq.addchildeventlistener(new childeventlistener() {         @override         public void onchildadded(datasnapshot datasnapshot, string s) {             system.out.println("child added: "+datasnapshot.getkey()+": "+datasnapshot.getvalue());         }          @override         public void onchildchanged(datasnapshot datasnapshot, string s) { }          @override         public void onchildremoved(datasnapshot datasnapshot) { }          @override         public void onchildmoved(datasnapshot datasnapshot, string s) { }          @override         public void oncancelled(firebaseerror firebaseerror) { }     });      console console = system.console();     if (console != null) {         console.format("press enter process.\n");         console.readline();     }     else {         system.out.println("sleeping 5 seconds, in hopes done then.");         thread.sleep(5000);     } } 

it prints out:

child added: frank: frank van puffelen child added: puf: frank van puffelen 

so seems work fine me.