input in C programming language -

i want code receive user floating number store 2 digit after decimal point

for example if user input

a=123.123456789 

a value equal 123.12

#include <stdio.h>  int func(int x,int digit,int con,char* s) {         int v;         v=x/digit;         v=v*digit;         x-=v;         if(con==1){            printf("%d %s(s) de r$ %.2f\n",(v/digit),s,(float)digit/100);             return x;         }         printf("%d %s(s) de r$ %.2f\n",(v/digit),s,(float)digit);         return x; } int main() {     int x=0;     float y;//if change double result true     scanf("%f",&y);     //y = ((int)(100.0 * y)) / 100.0;     x=(int)y;     y=y-x;      printf("notas:\n");      char* arr="nota";     x=func(x,100,0,arr);     x=func(x,50,0,arr);     x=func(x,20,0,arr);     x=func(x,10,0,arr);     x=func(x,5,0,arr);     x=func(x,2,0,arr);     printf("moedas:\n");     arr="moeda";     x=func(x,1,0,arr);     //mod     x=y*100;     x=func(x,50,1,arr);     x=func(x,25,1,arr);     x=func(x,10,1,arr);     x=func(x,5,1,arr);     x=func(x,1,1,arr);      return 0; } 

problem found in: https://www.urionlinejudge.com.br/judge/en/problems/view/1021

the value have 2 decimal places matter of displaying it, need print number of decimal places interested in, like

float value = 123.123456;  printf("%.2f\n", value); 

if want dynamicaly specify number, can use

float value    = 123.123456; int   decimals = 2;  printf("%.*f\n", decimals, value); 

if want store value string use sprintf() or better snprintf().

and taking input 2 decimals not make sense anyway because output should filtered instead of input, note after ignore decimals inserted user.

also, note floating point numbers cannot store exact numbers, leave 2 decimal places doing like

float value = ((int)(100.0 * 123.1234156)) / 100.0 

the actual value stored might be

123.1200000001 

which has more decimal places.

one thing try is

struct realnumber {     int integerpart;     int decimalpart; }; 

and handle input read them separately, dificult.