javascript - Run Bluebird Promises Sequentially, without return values? -

this question has been asked in variety of ways, not quite simply.

how promise.all rewritten promise1 runs before promise2?

var promise1 = function() { .. lots of promise stuff }; var promise2 = function() { .. lots more promise stuff };  promise.all([promise1, promise2]).then(function() {   log.info("ran promise1 & promise2"); }); 

promise.all runs promise1 & promise2 in parallel.

you can use promise.map concurrency option set 1.

var promise1 = function () {      return new promise(function (resolve, reject) {          console.log("promise1 pending");          settimeout(function () {              console.log("promise1 fulfilled");              resolve();          }, 1000)      })  };    var promise2 = function () {      return new promise(function (resolve, reject) {          console.log("promise2 pending");          settimeout(function () {              console.log("promise2 fulfilled");              resolve()          }, 50)      })  };    promise.map([promise1, promise2], function (promisefn) {      return promisefn(); //make sure here return promise  }, {concurrency: 1}); //it run promises sequentially     //it logs  //promise1 pending  //promise 1 fulfilled  //promise2 pending  //promise 2 fulfilled